b^2-9b-162=0

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Solution for b^2-9b-162=0 equation:


Simplifying
b2 + -9b + -162 = 0

Reorder the terms:
-162 + -9b + b2 = 0

Solving
-162 + -9b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-9 + -1b)(18 + -1b) = 0

Subproblem 1

Set the factor '(-9 + -1b)' equal to zero and attempt to solve: Simplifying -9 + -1b = 0 Solving -9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + -1b = 0 + 9 Combine like terms: -9 + 9 = 0 0 + -1b = 0 + 9 -1b = 0 + 9 Combine like terms: 0 + 9 = 9 -1b = 9 Divide each side by '-1'. b = -9 Simplifying b = -9

Subproblem 2

Set the factor '(18 + -1b)' equal to zero and attempt to solve: Simplifying 18 + -1b = 0 Solving 18 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-18' to each side of the equation. 18 + -18 + -1b = 0 + -18 Combine like terms: 18 + -18 = 0 0 + -1b = 0 + -18 -1b = 0 + -18 Combine like terms: 0 + -18 = -18 -1b = -18 Divide each side by '-1'. b = 18 Simplifying b = 18

Solution

b = {-9, 18}

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